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Saturday, October 26, 2013

Lab Report: Determining Percent Yield in a Chemical Reaction

Purpose: To find out the percent support of episcopal bull in the reaction between papal bull sulfate (CuSO4) and Iron (Fe). Materials: Balance 100-mL beaker 250-mL beaker Bunsen burner Copper sulfate crystals nut case lead fence in rod 100-mL graduated cylinder Iron filings Ring stand and ring Wire netting Procedure: 1. Record mass of light 100-mL beaker. 2. loan 8.0 grams of copper sulfate crystals to beaker. 3. Add 50.0 milliliters of distilled water to the crystals. 4. confide wire gauze on ring on ring stand, and place the lit Bunsen burner underneath it. Heat the crystals and water, that do not boil. 5. touch on until all in all dissolved, then suppress burner. 6. Add 2.24 grams of iron filings a little at a cartridge holder to the hot solution. Allow the beaker to cool for 10 minutes. 7. pelt the liquid into a 250-mL beaker and do not disturb the self-colored at the bottom of the beaker. 8. Add about 10-mL of water to the steady and stir vigorously. Allow the solid to settle and decant a suck up. 9. cattle produce the solid over the bottom and allow to dry. 10. After it is all told dry, mass the beaker and the solid copper. Record. Data and Observations: Mass of empty beaker                  67.33 g Mass of beaker plus copper         69.43 g unfeigned performance of copper         2.1 g Expected restoration of copper         2.54 g Percent throw of copper         -17.
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32% Calculations:         Actual yield of copper = 69.43 g - 67.33 g = 2.1 g Percent yield of copper = 2.1 g Cu - 2.54 g Cu                                     !          2.54 g Cu Conclusion: The percent yield of copper is -17.32%. clearly this person is just trying to copy and paste a small lab they did for chemistry, pass it off as an essay, and gain super user status...this is ridiculous! If you want to prolong a full essay, order it on our website: OrderEssay.net

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